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7n^2-41n-56=0
a = 7; b = -41; c = -56;
Δ = b2-4ac
Δ = -412-4·7·(-56)
Δ = 3249
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{3249}=57$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-41)-57}{2*7}=\frac{-16}{14} =-1+1/7 $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-41)+57}{2*7}=\frac{98}{14} =7 $
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